18x^2-50x=5

Solution for 18x^2-50x=5 equation:

18x^2-50x=5

We move all terms to the left:

18x^2-50x-(5)=0

a = 18; b = -50; c = -5;
Δ = b2-4ac
Δ = -502-4·18·(-5)
Δ = 2860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2860}=\sqrt{4*715}=\sqrt{4}*\sqrt{715}=2\sqrt{715}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{715}}{2*18}=\frac{50-2\sqrt{715}}{36}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{715}}{2*18}=\frac{50+2\sqrt{715}}{36}
$